Question

图示电路中，已知: US1 = 24V，US2 = 6V，IS =10A，R1 = 3 ，R2 = R3 = R4 = 2 。用戴维宁定理求电流I 。

Answer 1

先将R4两端断开，电流源开路，电压源短路，求出R4两端的等效电阻Req=R1//R2+R3=1.2+2=3.2Ω
然后求两端的等效电压，R4断开，最右边用KVL求出两端电压U=（Us1-Us2）*R2/(R1+R2)+Us2=13.2V
Ueq=13.2+Is*R3=33.2V

I=Ueq/(Req+R4)=6.15A