先化简再求值:x²-1/x²-2x+1/x+1/x-1*1-x/1+x,其中x=1/2
展开全部
x²-1/x²-2x+1/x+1/x-1*1-x/1+x
x²-1/x²-2x+1=(x+1)(x-1)/(x-1)^2=(x+1)(x-1)
x²-1/x²-2x+1/x+1/x-1=(x²-1/x²-2x+1)(x-1)/(x+1)=(x+1)(x-1)(x-1)/(x+1)=(x-1)^2
x²-1/x²-2x+1/x+1/x-1*1-x/1+x=(x-1)^2*1-x/1+x=(1-x)^3/x+1=(1/8)/(3/2)=1/12
x²-1/x²-2x+1=(x+1)(x-1)/(x-1)^2=(x+1)(x-1)
x²-1/x²-2x+1/x+1/x-1=(x²-1/x²-2x+1)(x-1)/(x+1)=(x+1)(x-1)(x-1)/(x+1)=(x-1)^2
x²-1/x²-2x+1/x+1/x-1*1-x/1+x=(x-1)^2*1-x/1+x=(1-x)^3/x+1=(1/8)/(3/2)=1/12
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
