Question

C# WinForm 如何实现程序重启？(加了一个进程判断，每次重启都弹出提示框)

//检查同一位置
Process current = Process.GetCurrentProcess();
Process[] processes = Process.GetProcessesByName(current.ProcessName);
foreach (Process process in processes)
{
if (process.Id != current.Id)
{
if (process.MainModule.FileName == current.MainModule.FileName)
{
MessageBox.Show("程序已经运行！\n如果未看见窗口，请点击右下角任务栏中的图标。", "农业智能控制", MessageBoxButtons.OK, MessageBoxIcon.Exclamation);
return;
}
}
}

Answer 1

自己重启可以用Application.Restart();

Answer 2

csdn上有类似问题的答案
http://bbs.csdn.net/topics/320149153