Question

求第一题和第三题详细答案

Answer 1

1)
z=x+yi
z=(x+yi-1)i=-y+(x-1)i
所以x+yi=-y+(x-1)i
x=-y,y=x-1
x=1/2,y=-1/2
模=√(1/4+1/4)=√2/2

BBBBBBBBBB
3)
z=(2-i)(1+i)/(1+i)(1-i)=(2+2i-i+1)/2=1/2*(3+i)=3/2+(1/2i)
DDDDDDDDDDDDDD

Answer 2

1 设：z=a+bi, a+bi=(a+bi-1)i=ai-b-i=-b+(a-1)i, , a=-b, b=a-1, b=-1/2, a=1/2,
|z|=√(a^2+b^2)=√2/2, 选 ：B
3 Z=((2-i)(1+I)/(1-i)(1+i)=(3+i)/2, 选： D

Answer 3

把分母变为实数，就ok了

Answer 4

望采纳谢谢

追答

3答案有错吧

Answer 5