Question

谁能写一个java打字游戏 超级简单的源码

随机出现很多字母 然后就打
还要算速度的（多少个字母一分钟）
打完后还会问要不要再来一次
下面我局个例子
(1) play another round（问要不要再来一次）
(2) exit the game（退出）
Selection: p（选择要 1 还是 2）

Text to Match: jomtqaaqnvnbyjzolihfifohfnpykr（随机出来的字母）
jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj（我打的字母）

INCORRECTLY TYPED, YOU GET A SPEED OF 0!（速度）

PS 不想要字母从天而降 谢谢

Answer 1

编好了，你自己运行下：
import java.util.Random;
import java.util.Scanner;

public class Test
{
public static Random r = new Random();

public static void printMenu()
{
System.out.println("(1) play another round");
System.out.println("(2) exit the game");
System.out.print("Selection:");
}

public static void main(String[] args) throws Exception
{
String content = null;
Scanner scan = new Scanner(System.in);

while(true)
{
printMenu();
content = scan.nextLine();
System.out.println();

//输入内容是2，则退出程序
if(content.equals("2")) break;

if(content.equals("1"))
{
System.out.print("Text to Match: ");
int count = r.nextInt(50) + 1;
char[] letters = new char[count];
for(int i=0;i<count;i++)
{
letters[i] = (char)(r.nextInt(26) + 97);
System.out.print(letters[i]);
}
System.out.print("\n ");
long startTime = System.currentTimeMillis();
int correctCount = 0;
content = scan.nextLine();

for(int i=0;i<count;i++)
{
if(content.charAt(i) == letters[i])
correctCount++;
}
long endTime = System.currentTimeMillis();
int time = (int)((endTime - startTime) / 1000);

if(correctCount == 0)
System.out.println("INCORRECTLY TYPED, YOU GET A SPEED OF 0!");
else
{
System.out.println("共花了" + time + "秒,正确率为：" + ((int)(((double)correctCount/count))*100) + "%");
}
}

System.out.println();
}
}

}