求问划红线这里怎么来的
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let
u=π-x
du=-dx
x=π/2, u=π/2
x=π, u=0
∫(π/2->π) (sinx)^m dx
=∫(π/2->0) (sinu)^m (-du)
=∫(0->π/2) (sinu)^m du
=∫(0->π/2) (sinx)^m dx
Jm
=(π/2)∫(0->π) (sinx)^m dx
=(π/2)∫(0->π/2) (sinx)^m dx + (π/2)∫(π/2->π) (sinx)^m dx
=(π/2)∫(0->π/2) (sinx)^m dx + (π/2)∫(0->π/2) (sinx)^m dx
=π∫(0->π/2) (sinx)^m dx
u=π-x
du=-dx
x=π/2, u=π/2
x=π, u=0
∫(π/2->π) (sinx)^m dx
=∫(π/2->0) (sinu)^m (-du)
=∫(0->π/2) (sinu)^m du
=∫(0->π/2) (sinx)^m dx
Jm
=(π/2)∫(0->π) (sinx)^m dx
=(π/2)∫(0->π/2) (sinx)^m dx + (π/2)∫(π/2->π) (sinx)^m dx
=(π/2)∫(0->π/2) (sinx)^m dx + (π/2)∫(0->π/2) (sinx)^m dx
=π∫(0->π/2) (sinx)^m dx
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