Question

用代数法化简下列逻辑函数？

请写下化简的步骤

Answer 1

1. F = A+A'B+BC+A'B'D

   = A(1+B)+A'B+BC+A'B'D

   = A+(AB+A'B)+BC+A'B'D

   = A+(A+A')B+BC+A'B'D

   = A+B+BC+A'B'D

   = A(1+B'D)+A'B'D+B(1+C)

   = A+(AB'D+A'B'D)+B

   = A+(A+A')B'D+B

   = A+B'D+B(1+D)

   = A+(B'D+BD)+B

   = A+B+(B'+B)D

   = A+B+D

2. F = [A'(B+C')]'(A+B'+C)(A'BC')'

   = [(A')'+(B+C')'](A+B'+C)[(A')'+B'+(C')']

   = [A+B'(C')'](A+B'+C)(A+B'+C)

   = (A+B'C)(A+B'+C)

   = AA+AB'C+AB'+B'B'C+AC+B'CC

   = A+AB'C+AB'+B'C+AC+B'C

   = A+AB'(C+1)+B'C+AC

   = A+AB'+B'C+AC

   = A(1+B'+C)+B'C

   = A+B'C