一加二分之一减六分之一减十二分之一减二十分之一减三十分之一减四十二分之一如何巧算?
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由题意得知,得出式子为 1+1/2-1/6-1/12-1/20-1/30-1/42
首先我们可以先把分母通分,然后再进行计算
1+1/2-(3/6+1/6+5/60+3/60+2/60+1/42)
=3/2-(2/3+10/60+1/42)
=3/2-(4/6+1/6+1/42)
=63/42-(35/42+1/42)
=63/42-36/42
=27/42
=9/14
首先我们可以先把分母通分,然后再进行计算
1+1/2-(3/6+1/6+5/60+3/60+2/60+1/42)
=3/2-(2/3+10/60+1/42)
=3/2-(4/6+1/6+1/42)
=63/42-(35/42+1/42)
=63/42-36/42
=27/42
=9/14
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答:
1+1/2-1/6-1/12-1/20-1/30-1/42
=(1+1/2)-(1/6+1/12)-(1/20+1/30)-1/42
=(2/2+1/2)-(2/12+1/12)-(3/60+2/60)+1/42
=3/2-1/4-1/12+1/42
=18/12-3/12-1/12+1/42
=7/6+1/42
=49/42+1/42
=25/21
1+1/2-1/6-1/12-1/20-1/30-1/42
=(1+1/2)-(1/6+1/12)-(1/20+1/30)-1/42
=(2/2+1/2)-(2/12+1/12)-(3/60+2/60)+1/42
=3/2-1/4-1/12+1/42
=18/12-3/12-1/12+1/42
=7/6+1/42
=49/42+1/42
=25/21
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1+1/2-1/6-1/12-1/20-1/30-1/42
=1+1/2-(1/2-1/3)-(1/3-1/4)-(1/4-1/5)
-(1/5-1/6)-(1/6-1/7)
=1+1/7
=8/7
=1+1/2-(1/2-1/3)-(1/3-1/4)-(1/4-1/5)
-(1/5-1/6)-(1/6-1/7)
=1+1/7
=8/7
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