Question

在matlab中用newton迭代法求解x-sinx=0根，急求，马上交作业了，谢谢高手来解答！！

Answer 1

f(x)=x-sin(x)
f'(x)=1-cos(x)
x=x-f(x)/f'(x)=x-(x-sin(x))/(1-cos(x))
程序如下
clear;
clc;
x=1;
while abs(x-sin(x))>0.001
x=x-(x-sin(x))/(1-cos(x));
end
x

得到结果

x =

0.1278