Question

若x与y互为倒数,a与b互为相反数,试求axy+b+x^2y^2

怎么做，初一数学题
列式也要啊

Answer 1

x与y互为倒数，则xy=1
a与b互为相反数,a+b=0
axy+b+x^2y^2 = a +b +(xy)^2 = 0+1^2 =1

Answer 2

23

Answer 3

∵x与y互为倒数，∵xy=1；
∵a与b互为相反数，∴a+b=0.

axy+b+x²y²
=a×1+b+(xy)²
=a+b+1²
=0+1
=1.