Question

如果a与2b互为倒数，负c与2分之d互为相反数，x的绝对值等3,求式子2ab-2c+d+3分之x的值。要过程

Answer 1

a*2b=1，ab=1/2
-c+d/2=0，d-2c=0
x=3或x=-3

2ab-2c+d+x/3
=2*(1/2)+(d-2c)+x/3
=1+0+x/3
=1+x/3
1）x=3时，原式=1+1=2
2）x=-3时，原式=1+（-1）=0

Answer 2

∵a×2b=2ab=1,-c+(d/2)=(-2c+d)/2=0,x=±3
∴2ab-2c+d+x/3
=1-0+3/3
=2
或：2ab-2c+d+x/3=1+0-1=0

Answer 3

a*2b=1;
-c+d/2=0,则d=2c
|x|=3;
2ab-2c+d+3=2-0+3=5
x=3或-3
x/(2ab-2c+d+3)=-3/5或3/5

Answer 4

a=1/2b,-c=-d/2,x=3
2ab=2*(1/2b)*b=1
-2c+d=-2*(d/2)+d=0
|X/3|=1
所以原式=1+|1|=0或2

Answer 5

a与2b互为倒数。所以2ab为1。2(-c+d/2)=0。所以分母为四。答案为3/4或-3/4

Answer 6

a*2b=1则2ab=1
d/2-c=0则d/2=c,2c=d
/x/=3,则x=3或-3
所以2ab-2c+d+3=1-d+d=3=4
x/2ab-2c+d+3=x/4
X/4= -3/4或3/4
式子2ab-2c+d+3分之x的值为-3/4或3/4