Question

(y-1)²+(y+3)²=26

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Answer 1

拆开括号，得y²-2y+1+y²+6y+9=26

移项、合并同类项，得y²+2y-8=0
即（y+4)(y-2)=0

所以y1=-4，y2=2

Answer 2

y^2-2y+1+y^2+6y+9=26
2y^2+4y-16=0
y^2+2y-8=0
(y+4)(y-2)=0

y1=-4
y2=2