分解下列因式
(1)8a^3x^2-2a^5x^2(2)a^2(x-y)+4y^2(y-x)(3)4a^2b^2-(a^2+b^2)^2(4)(x^2+4)^2-(2x+3)^2...
(1)8a^3x^2-2a^5x^2
(2)a^2(x-y)+4y^2(y-x)
(3)4a^2b^2-(a^2+b^2)^2
(4)(x^2+4)^2-(2x+3)^2 展开
(2)a^2(x-y)+4y^2(y-x)
(3)4a^2b^2-(a^2+b^2)^2
(4)(x^2+4)^2-(2x+3)^2 展开
展开全部
(1)
8a^3x^2-2a^5x^2
= 2a^3x^2(4-a^2)
= 2a^3x^2(2+a)(2-a)
(2)
a^2(x-y)+4y^2(y-x)
= (x-y)(a^2-4y^2)
= (x-y)(a+2y)(a-2y)
(3)
4a^2b^2-(a^2+b^2)^2
= (2ab+a^2+b^2)(2ab-a^2-b^2)
= -(a+b)^2(a-b)^2
(4)
(x^2+4)^2-(2x+3)^2
= (x^2+4+2x+3)(x^2+4-2x-3)
= (x^2+2x+7)(x^2-2x+1)
= (x^2+2x+7)(x^2-1)^2
~ 满意请采纳,不清楚请追问。
--------------------
~ 梳理知识,帮助别人,愉悦自己。
~ “数理无限”团队欢迎你
~ http://zhidao.baidu.com/team/view/%CA%FD%C0%ED%CE%DE%CF%DE
8a^3x^2-2a^5x^2
= 2a^3x^2(4-a^2)
= 2a^3x^2(2+a)(2-a)
(2)
a^2(x-y)+4y^2(y-x)
= (x-y)(a^2-4y^2)
= (x-y)(a+2y)(a-2y)
(3)
4a^2b^2-(a^2+b^2)^2
= (2ab+a^2+b^2)(2ab-a^2-b^2)
= -(a+b)^2(a-b)^2
(4)
(x^2+4)^2-(2x+3)^2
= (x^2+4+2x+3)(x^2+4-2x-3)
= (x^2+2x+7)(x^2-2x+1)
= (x^2+2x+7)(x^2-1)^2
~ 满意请采纳,不清楚请追问。
--------------------
~ 梳理知识,帮助别人,愉悦自己。
~ “数理无限”团队欢迎你
~ http://zhidao.baidu.com/team/view/%CA%FD%C0%ED%CE%DE%CF%DE
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
(1)8a^3x^2-2a^5x^2
=2a³x²(4-a²)
=2a³x²(2+a)(2-a)
(2)a^2(x-y)+4y^2(y-x)
=(x-y)(a²-4y²)
=(x-y)(a+2y)(a-2y)
(3)4a^2b^2-(a^2+b^2)^2
=(2ab+a²+b²)(2ab-a²-b²)
=-(a+b)²(a-b)²
(4)(x^2+4)^2-(2x+3)^2
=(x²+4+2x+3)(x²+4-2x-3)
=(x²+2x+7)(x²-2x+1)
=(x²+2x+7)(x-1)²
=2a³x²(4-a²)
=2a³x²(2+a)(2-a)
(2)a^2(x-y)+4y^2(y-x)
=(x-y)(a²-4y²)
=(x-y)(a+2y)(a-2y)
(3)4a^2b^2-(a^2+b^2)^2
=(2ab+a²+b²)(2ab-a²-b²)
=-(a+b)²(a-b)²
(4)(x^2+4)^2-(2x+3)^2
=(x²+4+2x+3)(x²+4-2x-3)
=(x²+2x+7)(x²-2x+1)
=(x²+2x+7)(x-1)²
本回答被提问者采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询