一个正方形,六个面上分别写着六个连续的整数,且每个相对面上的两个数之和相等,如图,你能看到的数为7
一个正方形,六个面上分别写着六个连续的整数,且每个相对面上的两个数之和相等,如图,你能看到的数为7、10、11,则六个整数的和()A.51B.52C.57D.58...
一个正方形,六个面上分别写着六个连续的整数,且每个相对面上的两个数之和相等,如图,你能看到的数为7、10、11,则六个整数的和( ) A.51 B.52 C.57 D.58
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Because the sum of the two numbers on each opposite side is equal, that means that the sum of the three numbers is equal to the final sum. Then 51.3 is the The first group is opposite, that is, 1 / 3 of the total result. If calculated this way, 52 can not go to 358 and can not be divided by three, so b and d rule out. So now there are only 51 and 57 pages left, a and c. If it's five in one, you'll have an eight out of nine, which means The sum of 51-7 + 8 + 9 + 10 plus 11. Be equal to 16. 16 doesn't extend to the next 11, so a rules it out. There's only one c left. The number for the C option is 57, and then 57-7-10 minus 8-9-11. That's 57.45. The final result is equal to 12. And the next digit of 11 is exactly 12, which is exactly the combination of 7 8 9 10 11 12.The last option is dead.根据以上所有的假设方法。选择为c57。
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