Question

用java编写乘号菱形金字塔的程序

Answer 1

根据下面代码自己修改吧，这肯定是你想要的

public static void main(String[] args) {
int i, j, k;
for (i = 1; i <= 3; i++) {
for (j = 1; j <= 3 - i; j++)
System.out.print(" ");
for (k = 1; k <= 2 * i - 1; k++)
System.out.print("*");
System.out.println("");
}
for (i = 1; i <= 2; i++) {
for (j = 1; j <= i; j++)
System.out.print(" ");
for (k = 1; k <= 5 - 2 * i; k++)
System.out.print("*");
System.out.println("");
}
}

Answer 2

int i = 10;
for (int j = 1; j <= i; j++) {
//控制星号数量
int times = (2*j)-1;
//控制空格数量
int time=0;
//根据规律，做出限定
while(time!=(i-j))
{
System.out.print(" ");
time++;
}
while (times != 0) {
System.out.print("*");
times--;
}
System.out.print("\n");
}
for (int j = i-1; j >0; j--) {
//控制星号数量
int times = (2*j)-1;
//控制空格数量
int time=0;
//根据规律，做出限定
while(time!=(i-j))
{
System.out.print(" ");
time++;
}
while (times != 0) {
System.out.print("*");
times--;
}
System.out.print("\n");
}
放到你的main方法里，已验证！

Answer 3

public static void main(String[] args) {
// TODO Auto-generated method stub
int i = 5;
for (int j = 1; j <= i; j++) {
//控制星号数量
int times = (2*j)-1;
//控制空格数量
int time=0;
//根据规律，做出限定
while(time!=(i-j))
{
System.out.print(" ");
time++;
}
while (times != 0) {
System.out.print("*");
times--;
}
System.out.print("\n");
}
}

Answer 4

for循环就可以了 2层

第一层是行 第二层是列

Answer 5

菱形正三角倒三角？