两道小学数学递等式!速度!!!!
7.5×2.3+1.9×2.5+22.5×0.4(1+0.12+0.23)×(0.12+0.23+0.34)—(1+0.12+0.23+0.34)×(0.12+0.23)...
7.5×2.3+1.9×2.5+22.5×0.4
(1+0.12+0.23)×(0.12+0.23+0.34)—(1+0.12+0.23+0.34)×(0.12+0.23)
小学5年级没学过.....
我要巧算,谢谢 展开
(1+0.12+0.23)×(0.12+0.23+0.34)—(1+0.12+0.23+0.34)×(0.12+0.23)
小学5年级没学过.....
我要巧算,谢谢 展开
3个回答
展开全部
7.5*2.3+1.9*2.5+22.5*0.4
=2.5*3*2.3+1.9+2.5+2.5*9*0.4
=2.5*(6.9+1.9+3.6)
=2.5*12.4
=2.5*4*3.1
=31
(1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.12+0.23)
=(1+0.12+0.23)*(0.12+0.23)+(1+0.12+0.23)*0.34-(1+0.12+0.23)*(0.12+0.23)-0.34*(0.12+0.23)
=0+0.34*(1+0.12+0.23-0.12-0.23)
=0.34
=2.5*3*2.3+1.9+2.5+2.5*9*0.4
=2.5*(6.9+1.9+3.6)
=2.5*12.4
=2.5*4*3.1
=31
(1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.12+0.23)
=(1+0.12+0.23)*(0.12+0.23)+(1+0.12+0.23)*0.34-(1+0.12+0.23)*(0.12+0.23)-0.34*(0.12+0.23)
=0+0.34*(1+0.12+0.23-0.12-0.23)
=0.34
展开全部
第一题用计算器
第二题设0.12+0.23为a,0.12+0.23+0.34为b
(1+a)×b-(1+b)×a
=ab+b-ab-a
=b-a
=0.12
第二题设0.12+0.23为a,0.12+0.23+0.34为b
(1+a)×b-(1+b)×a
=ab+b-ab-a
=b-a
=0.12
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
(1)3×2.5×2.3+2.5×1.9+22.5×0.4=2.5×8.8+22.5×0.4=2.5×22×0.4+22.5×0.4=0.4×55=22
(2)设0.12+0.23=a
则原式=(1+a)×(a+0.34)—(1+a+0.34)×a=a+0.34+a²+0.34a—a—a²——0.34a=0.34
刘子玮和汤锐的角逐
(2)设0.12+0.23=a
则原式=(1+a)×(a+0.34)—(1+a+0.34)×a=a+0.34+a²+0.34a—a—a²——0.34a=0.34
刘子玮和汤锐的角逐
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询