七年级数学,求解,必采纳,在线等,急急急急急急
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(1)x²y+xy²
=xy(x+y)
(2)4x²-16y²
=(2x)²-(4y)²
=(2x+4y)(2x-4y)
(3)x²-12x+36
=(x-6)²
(4)x²-11x+30
=(x-5)(x-6)
(5)3x²-12x+12
=3(x²-4x+4)
=3(x-2)²
(6)-2x²+6x-4
=-2(x²-3x+2)
=-2(x-1)(x-2)
(7)x²-16y²+x-4y
=(x+4y)(x-4y)+(x-4y)
=(x+4y+1)(x-4y)
(8)xy-xz+y-z
=x(y-z)+(y-z)
=(x+1)(y-z)
=xy(x+y)
(2)4x²-16y²
=(2x)²-(4y)²
=(2x+4y)(2x-4y)
(3)x²-12x+36
=(x-6)²
(4)x²-11x+30
=(x-5)(x-6)
(5)3x²-12x+12
=3(x²-4x+4)
=3(x-2)²
(6)-2x²+6x-4
=-2(x²-3x+2)
=-2(x-1)(x-2)
(7)x²-16y²+x-4y
=(x+4y)(x-4y)+(x-4y)
=(x+4y+1)(x-4y)
(8)xy-xz+y-z
=x(y-z)+(y-z)
=(x+1)(y-z)
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采纳采纳!真的!
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