Question

2log3 2-log32/9+log3 8-5^log5 3

我要详细的步骤

Answer 1

应用公式：
①log3(M/N)=log3(M)-log3(N)
②log3(Mⁿ)=nlog3(M)
③M^logM(N)=N

解：
2log3(2)-log3(2/9)+log3(8)-5^log5(3)
=2log3(2)-[log3(2)-log3(9)]+3log3(2)-3
=2log3(2)-log3(2)+2log3(3)+3log3(2)-3
=4log3(2)+2-3
=4log3(2)-1

Answer 2

2log3^2-log3^(32/9)+log3^8-3
=log3^2^2-log3^(32/9)+log3^8-3
=log3^[2^2*8/(32/9)]-3
=log3^9-3
=log3^(3^2)-3
=2-3
=-1