Question

分解因式

分解因式：12ab²（x-y）²+24a²b²（y-x）²+18ab（y-x）³

Answer 1

解：原式=12ab²(x-y)²-24a²b²(x-y)²-18ab(x-y)³
=6ab(x-y)²[2-4ab-3(x-y)]
=6ab(x-y)²【2-4ab-3x+3y】

Answer 2

=12ab2(x-y)2-24a2b2(x-y)2-18ab(x-y)3
=6ab(x-y)2{2-4ab-3(x-y)}
=6ab(x-y)2{2-4ab-3x+3y}