1/[log1/2(1/3)+log(1/4)(1/3)]的值
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你好：
此题主要用了换底公式
1/[log1/2(1/3)+log(1/4)(1/3)]
=1/[log(1/2)(1/3) +log(1/2)²(1/3)]
=1/[log(1/2)(1/3) +(1/2)log(1/2)(1/3)]
=1/[(3/2)log(2^(-1))(3^(-1))]
=1/[(3/2)log(2)(3)]
=(2/3)log(3)(2)
谢谢
此题主要用了换底公式
1/[log1/2(1/3)+log(1/4)(1/3)]
=1/[log(1/2)(1/3) +log(1/2)²(1/3)]
=1/[log(1/2)(1/3) +(1/2)log(1/2)(1/3)]
=1/[(3/2)log(2^(-1))(3^(-1))]
=1/[(3/2)log(2)(3)]
=(2/3)log(3)(2)
谢谢
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