x+2y+X-2y分之4y的平方+4y^2-x的平方分之4x平方y
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你这样叙述的题就有问题:那个是分母?
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你最好排照发来。
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x+2y+4y²/(x-2y)+4x²y/(4y²-x²)
=(x+2y)(x-2y)/(x-2y)+4y²/(x-2y)+4x²y/(2y+x)(2y-x)
=(x²-4y²+4y²)/(x-2y)-4x²y/(x+2y)(x-2y)
=x²/(x-2y)-4x²y/(x+2y)(x-2y)
=x²(x+2y)/(x+2y)(x-2y)-4x²y/(x+2y)(x-2y)
=(x³+2x²y-4x²y)/(x+2y)(x-2y)
=x²(x-2y)/(x+2y)(x-2y)
=x²/(x+2y)
=(x+2y)(x-2y)/(x-2y)+4y²/(x-2y)+4x²y/(2y+x)(2y-x)
=(x²-4y²+4y²)/(x-2y)-4x²y/(x+2y)(x-2y)
=x²/(x-2y)-4x²y/(x+2y)(x-2y)
=x²(x+2y)/(x+2y)(x-2y)-4x²y/(x+2y)(x-2y)
=(x³+2x²y-4x²y)/(x+2y)(x-2y)
=x²(x-2y)/(x+2y)(x-2y)
=x²/(x+2y)
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