Question

x^4-9x^3-18x^2-184x+192=0我想要具体的步骤

Answer 1

x^4-9x³-10x²-8x²-184x+192=0
x²(x²-9x-10)-(8x²+184x-192)=0
x²(x+1)(x-10)-8(x²+23x-24)=0
x²(x+1)(x-10)-8(x-1)(x+24)=0...
好像算到这里没有公因式了
是不是系数的正负有问题?
我觉得184x前面的系数应该是+号
这样的话
x^4-9x³-10x²-8x²+184x+192=0
x²(x²-9x-10)-(8x²-184x-192)=0
x²(x+1)(x-10)-8(x²-23x-24)=0
x²(x+1)(x-10)-8(x+1)(x-24)=0
(x+1)(x³-10x²-8x+192)=0
(x+1)(x³-10x²+24x-32x+192)=0
(x+1)[x(x-4)(x-6)-32(x-6)]=0
(x+1)(x-6)(x²-4x-32)=0
(x+1)(x-6)(x+4)(x-8)=0