Question

高数作业求解答

Answer 1

f(x)
=√(x^2-1) ; x<1
=b ; x=1
=a+arcsin1 ; x>1
f(1-) =lim(x->1-) √(x^2-1) = 0
f(1) =b
f(1+)=lim(x->1+) (a+arcsin1 ) = a+arcsin1
f(1-)=f(1) =f(1+)
b=0, a= -arcsin1