对数计算怎么算?
展开全部
灵活运用公式,如下:
当a>0且a≠1时,M>0,N>0,那么: (1)log(a)(MN)=log(a)(M)+log(a)(N); (2)log(a)(M/N)=log(a)(M)-log(a)(N); (3)log(a)(M^n)=nlog(a)(M) (n∈R) (4)log(a^n)(M)=1/nlog(a)(M)(n∈R) (5)换底公式:log(A)M=log(b)M/log(b)A (b>0且b≠1) (6)a^(log(b)n)=n^(log(b)a) 证明: 设a=n^x则a^(log(b)n)=(n^x)^log(b)n=n^(x·log(b)n)=n^log(b)(n^x)=n^(log(b)a) (7)对数恒等式:a^log(a)N=N; log(a)a^b=b (8)由幂的对数的运算性质可得(推导公式)
当a>0且a≠1时,M>0,N>0,那么: (1)log(a)(MN)=log(a)(M)+log(a)(N); (2)log(a)(M/N)=log(a)(M)-log(a)(N); (3)log(a)(M^n)=nlog(a)(M) (n∈R) (4)log(a^n)(M)=1/nlog(a)(M)(n∈R) (5)换底公式:log(A)M=log(b)M/log(b)A (b>0且b≠1) (6)a^(log(b)n)=n^(log(b)a) 证明: 设a=n^x则a^(log(b)n)=(n^x)^log(b)n=n^(x·log(b)n)=n^log(b)(n^x)=n^(log(b)a) (7)对数恒等式:a^log(a)N=N; log(a)a^b=b (8)由幂的对数的运算性质可得(推导公式)
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询