Question

C程编程问题.计算用0-9这些数字可以组成多少个没有重复数字的三位偶数,按每行6个输出,最后将输出的数求和.

Answer 1

#include "stdio.h"
#include "stdlib.h"
void main()
{
int hundred,ten,one;
int sum=0;
int count=0;
for (int i=100;i<999;i++)
{
hundred=i/100;
ten=(i-hundred*100)/10;
one=i%10;

if ((hundred==ten)||(hundred==one)||(ten==one)||(one%2==1))
continue;
else
{
count+=1;
printf("%d %d %d ",hundred,ten,one);
if ((count%6)==0)
{
printf("\n");
}
sum=sum+i;
}
}
printf("SUM of this number is %d\n",sum);

}

Answer 2

#include<stdio.h>
#include<stdlib.h>
void main()
{
int hundred,ten,one;
int sum=0;
int count=0;
for (int i=100;i<999;i++)
{
hundred=i/100;
ten=(i-hundred*100)/10;
one=i%10;

if ((hundred==ten)||(hundred==one)||(ten==one)||(one%2==1))
continue;
else
{
count+=1;
printf("%d %d %d ",hundred,ten,one);
if ((count%6)==0)
{
printf("\n");
}
sum=sum+i;
}
}
printf("SUM of this number is %d\n",sum);
system("pause");
}