Question

初二数学因式分解

已知多项式4x³-7x²-kx+4有一个因式x-2，求k

Answer 1

令另一个因式是A
4x³-7x²-kx+4=A(x-2)

x=2,x-2=0
则右边等于0
所以左边也等于0
所以x=2
4x³-7x²-kx+4=32-28-2k+4=0
k=4

Answer 2

5.6/8=0.7 7/0.1=70
0.45/0.15=3 7.2/0.9=8
5/4=1.25
6.8/0.17=40
2/0.5=4
0.53/0.01=53
2.1/0.7=3
8.3/0.1=83
4.6/10=0.46
0.84/0.14=6
3/5=0.6
0.57/0.19=3
4/10=0.4
7.2/0.06=120
5.6/0.02=280
9.7/0.97=10
0.77/0.11=7
9.1/0.7=13
3/0.5=6

0.41/0.1=4.1
0.13/10=0.03
0.64/0.16=4
0.36/0.09=4
0.05/0.02=2.5
0.78/3=0.26