Question

已知R1=10Ω,R2=20Ω,将R1和R2串联后接在6V电源上,求(1)电路中的电流; (2)R1和R2的两端电压各是多少?

Answer 1

如果R1和R2串联，则电路总电阻R=R1+R2=30欧姆
所以
(1)电流I=6/30=0.2A
(2)利用分压定理，R1端电压=6*R1/(R1+R2)=2V
R2端电压=6*R2/(R1+R2)=4V

Answer 2

1)I=U/(R1+R2)=6/30=0.2A

2)U1=I*R1=0.2*10=2v

U2=I*R2=20*0.2=4V