甲数是乙丙丁之和的二分之一,乙数是甲丙丁之和的三分之一,丙是甲乙丁之和的四分之一,已知丁数260
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x为甲,y为乙,z为丙
x=(y+z+260)/2
y=(x+z+260/3
z=(x+y+260)/4
1.2x=y+z+260
2.3y=x+z+260
3.4z=x+y+260
2式减1式得3y-2x=x-y即4y-3x=0即3x=4y即15x=20y
2式乘以4得12y=4x+4z+1040,加3式得12y=x+y+260+4x+1040即11y=5x+1300即33y=15x+3900
即33y=20y+3900,即13y=3900得y=300,因3x=4y=1200,故x=400
将x,y代入3式得4z=400+300+260=960,得z=240
答案为,甲为400,乙为300,丙为240,丁为260
x=(y+z+260)/2
y=(x+z+260/3
z=(x+y+260)/4
1.2x=y+z+260
2.3y=x+z+260
3.4z=x+y+260
2式减1式得3y-2x=x-y即4y-3x=0即3x=4y即15x=20y
2式乘以4得12y=4x+4z+1040,加3式得12y=x+y+260+4x+1040即11y=5x+1300即33y=15x+3900
即33y=20y+3900,即13y=3900得y=300,因3x=4y=1200,故x=400
将x,y代入3式得4z=400+300+260=960,得z=240
答案为,甲为400,乙为300,丙为240,丁为260
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