Question

php上传函数问题

用以下代码，关于上传的，总是出现问题
<?php
if ($upfile=="none")
{
echo "没有选择文件";
echo "<p>";
echo "点<a href=\"8-15.php\">这里</a>返回";
}
else
{
$filepath="images/";
$filename=$filepath.$upfile_name;
echo $upfile_name;
echo "<p>";
echo $upfile_size;
echo "<p>";
echo $upfile_type;
if (copy($upfile, $filename))
{
unlink($upfile);
echo "<p>";
echo "指定文件已经上传!";
echo "<p>";
echo "点<a href=\"8-15.php\">这里</a>返回";
}
else
{
echo "文件上传失败!";
}
}
?>
出现错误，但是没发现错误在哪儿。
Notice: Undefined variable: upfile in D:\wamp\www\part01\8-16.php on line 2

Notice: Undefined variable: upfile_name in D:\wamp\www\part01\8-16.php on line 11

Notice: Undefined variable: upfile_name in D:\wamp\www\part01\8-16.php on line 12

Notice: Undefined variable: upfile_size in D:\wamp\www\part01\8-16.php on line 14

Notice: Undefined variable: upfile_type in D:\wamp\www\part01\8-16.php on line 16

Notice: Undefined variable: upfile in D:\wamp\www\part01\8-16.php on line 17

Warning: copy() [function.copy]: Filename cannot be empty in D:\wamp\www\part01\8-16.php on line 17
文件上传失败!

Answer 1

这么多的错误提示，文件肯定上传失败了。你先把错误都解决了先啊 。而且我看你这个文件上传代码并不完整，而且关键代码一句都没。你还是重新再找一个吧

追问

我照书上打的，，，

追答

。。。打的好打的妙打的呱呱叫