已知关于x的方程x-1/x-4=m/x-4有增根，则m的值是
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x/(x-1)-(x-1)/(x-2)=(x-3)/(x-4)-(x-4)/(x-5),
(x-1+1)/(x-1)-(x-2+1)/(x-2)=(x-4+1)/(x-4)-(x-5+1)/(x-5),
1+1/(x-1)-1-1/(x-2)=1+1/(x-4)-1-1/(x-5),
1/(x-1)-1/(x-2)=1/(x-4)-1/(x-5),
1/(x-1)+1/(x-5)=1/(x-4)+1/(x-2),
(x-5+x-1)/[(x-1)(x-5)]=(x-2+x-4)/[(x-4)(x-2)],
(2x-6)/(x^2-6x+5)=(2x-6)/(x^2-6x+8),
(2x-6)[1/(x^2-6x+5)-1/(x^2-6x+8)]=0,
(2x-6)(x^2-6x+8-x^2+6x-5)/[(x^2-6x+5)(x^2-6x+8)]=0,
3(2x-6)/[(x^2-6x+5)(x^2-6x+8)]=0,
2x-6=0,
x=3.
(x-1+1)/(x-1)-(x-2+1)/(x-2)=(x-4+1)/(x-4)-(x-5+1)/(x-5),
1+1/(x-1)-1-1/(x-2)=1+1/(x-4)-1-1/(x-5),
1/(x-1)-1/(x-2)=1/(x-4)-1/(x-5),
1/(x-1)+1/(x-5)=1/(x-4)+1/(x-2),
(x-5+x-1)/[(x-1)(x-5)]=(x-2+x-4)/[(x-4)(x-2)],
(2x-6)/(x^2-6x+5)=(2x-6)/(x^2-6x+8),
(2x-6)[1/(x^2-6x+5)-1/(x^2-6x+8)]=0,
(2x-6)(x^2-6x+8-x^2+6x-5)/[(x^2-6x+5)(x^2-6x+8)]=0,
3(2x-6)/[(x^2-6x+5)(x^2-6x+8)]=0,
2x-6=0,
x=3.
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