Question

JAVA小白求回答~急~ 我想通过在我做的窗口中的文本框内输入不同的数字，点确定按钮之后，弹出不同的窗口

出现了bug不知道怎么解决
代码在这里：
import java.awt.BorderLayout;
import java.awt.FlowLayout;
import java.awt.Font;
import java.awt.GridLayout;
import java.awt.event.ActionListener;

import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;
import javax.swing.JTextField;

import javafx.event.ActionEvent;

public class RobotInterface {
private JFrame frame1 = new JFrame("come on");
private JLabel tit = new JLabel("Please select an option:") ;
private JPanel pan1 = new JPanel();
private JPanel pan2 = new JPanel();
public RobotInterface(){
Font fon2 = new Font("Comic",Font.BOLD,30);
frame1.setLayout(new BorderLayout(3,3));
tit.setFont(fon2);

pan1.setLayout(new GridLayout(2,3,3,3));
JButton lab1 = new JButton("1. Fish ");
JButton lab2 = new JButton("2. Meat ");
JButton lab3 = new JButton("3. Rice ");
JButton lab4 = new JButton("4. Noodle");
JButton lab5 = new JButton("5. Drink ");
Font fon1 = new Font("Comic",Font.BOLD,38);
lab1.setFont(fon1);
lab2.setFont(fon1);
lab3.setFont(fon1);
lab4.setFont(fon1);
lab5.setFont(fon1);
pan1.add(lab1);
pan1.add(lab2);
pan1.add(lab3);
pan1.add(lab4);
pan1.add(lab5);

pan2.setLayout(new FlowLayout(FlowLayout.RIGHT,3,3));
JTextField select = new JTextField(30);
JLabel tex = new JLabel("Option selected:");
JButton sub = new JButton("OK");
tex.setFont(fon2);
sub.setFont(fon2);
pan2.add(tex);
pan2.add(select);
pan2.add(sub);

sub.addActionListener(new ActionListener(){
public void actionPerformed(ActionEvent arg0){
if (arg0.getSource()== sub){
String tnum = select.getText();
int num = Integer.parseInt(tnum);
if (num == 1){
new FishMenu();
}
else{
System.out.println("otherwise");
}
}
}

});

frame1.add(tit,BorderLayout.NORTH);
frame1.add(pan1,BorderLayout.CENTER);
frame1.add(pan2,BorderLayout.SOUTH);
frame1.setVisible(true);
}

}
56行：
The type new ActionListener(){} must implement the inherited abstract method ActionListener.actionPerformed(ActionEvent)
57行：
The method actionPerformed(ActionEvent) from the type new ActionListener(){} is never used locally

Answer 1

把actionPerformen方法删掉，然后鼠标放到ActionListener上按下ctrl+1实现里边的方法

Answer 2

你可以把错误信息也贴出来

追问

补充了(,,•́ . •̀,,)