
求(2x-1)/(x+1)≤2中x的取值范围。
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(2x - 1)/(x + 1) ≤ 2
(2x - 1)/(x + 1) - 2 ≤ 0
通分得:
[2x - 1 - 2(x + 1)]/(x + 1) ≤ 0
-3/(x + 1)≤ 0
x + 1 > 0
x > -1
(2x - 1)/(x + 1) - 2 ≤ 0
通分得:
[2x - 1 - 2(x + 1)]/(x + 1) ≤ 0
-3/(x + 1)≤ 0
x + 1 > 0
x > -1
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