2个回答
2017-10-24 · 知道合伙人教育行家
关注
展开全部
(a-b)/[a^(1/3)-b^(1/3)]-(a+b)/[a^(1/3)+b^(1/3)]
=[a^(2/3)+(ab)^(1/3)+b^(2/3)]-[a^(2/3)-(ab)^(1/3)+b^(2/3)]
=a^(2/3)+(ab)^(1/3)+b^(2/3)-a^(2/3)+(ab)^(1/3)-b^(2/3)
=2(ab)^(1/3)
=[a^(2/3)+(ab)^(1/3)+b^(2/3)]-[a^(2/3)-(ab)^(1/3)+b^(2/3)]
=a^(2/3)+(ab)^(1/3)+b^(2/3)-a^(2/3)+(ab)^(1/3)-b^(2/3)
=2(ab)^(1/3)
追问
那这样做是对的吧?
本回答被提问者和网友采纳
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询