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系数矩阵行列式为 0 时,有非零解。 |A| =
|1-λ -2 4|
|2 3-λ 1|
|1 1 1-λ|
|A| =
|1-λ λ-3 3+2λ-λ^2|
|2 1-λ 2λ-1|
|1 0 0|
|A| =
|λ-3 (3-λ)(1+λ)|
|1-λ 2λ-1|
|A| = (λ-3)*
|1 -(1+λ)|
|1-λ 2λ-1|
|A| = (λ-3)(2λ-1+1-λ^2) = λ(λ-3)(2-λ) = 0
得 λ = 0 ,或 λ = 2,或 λ = 3.
|1-λ -2 4|
|2 3-λ 1|
|1 1 1-λ|
|A| =
|1-λ λ-3 3+2λ-λ^2|
|2 1-λ 2λ-1|
|1 0 0|
|A| =
|λ-3 (3-λ)(1+λ)|
|1-λ 2λ-1|
|A| = (λ-3)*
|1 -(1+λ)|
|1-λ 2λ-1|
|A| = (λ-3)(2λ-1+1-λ^2) = λ(λ-3)(2-λ) = 0
得 λ = 0 ,或 λ = 2,或 λ = 3.
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