Question

麻烦哪位帮我解答一下！

麻烦帮我解一下这个方程，并写出过程，说明一下这几个括号怎么去，方程是450X-(310.02+240X)-(450X*0.13-145X-30.4)*0.12=0
X是未知数，麻烦解答一下！

Answer 1

450X-(310.02+240X)-(450X*0.13-145X-30.4)*0.12=0450X-310.02-240X-(450X*0.13-145X-30.4)*0.12=0210X-310.02-(58.5X-145X-30.4)*0.12=0210X-310.02-(-86.5X-30.4)*0.12=0210X-310.02-(-10.38X-3.648)=0210X-310.02+10.38X+3.648=0220.38X=306.372x≈1.3902

Answer 2

450X-(310.02+240X)-(450X*0.13-145X-30.4)*0.12=0
450X-310.02-240X-(450X*0.13-145X-30.4)*0.12=0
210X-310.02-(58.5X-145X-30.4)*0.12=0
210X-310.02-(-86.5X-30.4)*0.12=0
210X-310.02-(-10.38X-3.648)=0
210X-310.02+10.38X+3.648=0
220.38X=306.372
x≈1.3902

Answer 3

Answer 4

450X-310.02-240X-7.02X+17.4+3.648=0,X=1.42364765001478

Answer 5

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