Question

给我下列函数图像五点法的点.也需要对应的Y值 y=1/2sin2x y=sinscosx y=2sinx/2

Answer 1

y=1/2sin2x
T=2π/2=π
所以x=-π/2,y=1/2sin(-π)=0
x=-π/4,y=1/2sin(-π/2)=-1/2
x=0,y=1/2sin0=0
x=π/4,y=1/2sin(π/2)=1/2
x=π/2,y=1/2sinπ=0
y=sinxcosx=1/2sin2x
和上面一样
y=2sinx/2
T=2π/(1/2)=4π
所以
x=-2π,y=2sin(-π)=0
x=-π,y=2sin(-π/2)=-2
x=0,y=2sin0=0
x=π,y=2sin(π/2)=2
x=2π,y=2sinπ=0