Question

用洛必达法则求下列极限 limx趋向0 [(e^x-e^-x-2x)/(x-sinx)]

Answer 1

limx->0 [(e^x-e^-x-2x)/(x-sinx)]
=limx->0 [(e^x+e^-x-2)/(1-cosx)]
=limx->0[(e^x-e^-x)/ sinx]
=limx->0 [(e^x+e^-x)/cosx]
=(1+1)/1
=2