Question

已知多项式mx的五次方+nx的三次方+px-4当x=2时，此多项式的值为5，求当x=2时，多项式的值是多少？

Answer 1

题目问题应该是求x=-2时的值吧
当x=2时,mx＾5+nx＾3+px-4=32m+8n+2p-4=5
32m+8n+2p=9
当x=-2时,mx＾5+nx＾3+px-4
=-32m-8n-2p-4
=-(32m+8n+2p)-4
=-9-4
=-13

Answer 2

当x=2时,mx＾5+nx＾3+px-4=32m+8n+2p-4=5
32m+8n+2p=9
当x=-2时,mx＾5+nx＾3+px-4
=-32m-8n-2p-4
=-(32m+8n+2p)-4
=-9-4
=-13

Answer 3

5

Answer 4

-13