Question

初二数学，12题，如图，求解，要过程，谢谢

Answer 1

【解析】根据函数图象和题意可以求出开始的速度为80海里/时，故障排除后的速度是100海里/时，设计划行驶的路程是a海里，就可以由时间之间的关系建立方程求出路程，再由路程除以速度就可以求出计划到达时间：
由图象及题意，得：故障前的速度为：80÷1=80海里/时，故障后的速度为：（180－80）÷1=100海里/时．
设航行额全程由a海里，由题意，a/80=2+(a-80）/100得，解得：a=480。
则原计划行驶的时间为：480÷80=6小时，故计划准点到达的时刻为：7：00。

追问

谢谢

Answer 2

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追问

您怎么了

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