方程组 6x+5y=360 ;8x+4y=440 用加减法 怎么解?
2个回答
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6x + 5y = 360,
8x + 4y = 440,
加减法消元,
6x + 5y = 360,
12x + 10y = 720,
8x + 4y = 440,
4x + 2y = 220,
12x + 6y = 660,
( 12x +10y ) - ( 12x +6y ) = 720 - 660,
4y = 60,
y = 15,
8x + 60 = 440,
8x = 380,
4x = 190,
2x = 95,
x = 47.5
解方程组,
x = 47.5,
y = 15,
8x + 4y = 440,
加减法消元,
6x + 5y = 360,
12x + 10y = 720,
8x + 4y = 440,
4x + 2y = 220,
12x + 6y = 660,
( 12x +10y ) - ( 12x +6y ) = 720 - 660,
4y = 60,
y = 15,
8x + 60 = 440,
8x = 380,
4x = 190,
2x = 95,
x = 47.5
解方程组,
x = 47.5,
y = 15,
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