Question

easyUi dategrid 需要的这种json格式 用list<实体> 要怎么转才能转成这样

[{
"id":1,
"name":"C",
"size":"",
"date":"02/19/2010",
"children":[{
"id":2,
"name":"Program Files",
"size":"120 MB",
"date":"03/20/2010",
"children":[{
"id":21,
"name":"Java",
"size":"",
"date":"01/13/2010",
"state":"closed",
"children":[{
"id":211,
"name":"java.exe",
"size":"142 KB",
"date":"01/13/2010"
},{
"id":212,
"name":"jawt.dll",
"size":"5 KB",
"date":"01/13/2010"
}]
},{
"id":22,
"name":"MySQL",
"size":"",
"date":"01/13/2010",
"state":"closed",
"children":[{
"id":221,
"name":"my.ini",
"size":"10 KB",
"date":"02/26/2009"
},{
"id":222,
"name":"my-huge.ini",
"size":"5 KB",
"date":"02/26/2009"
},{
"id":223,
"name":"my-large.ini",
"size":"5 KB",
"date":"02/26/2009"
}]
}]
},{
"id":3,
"name":"eclipse",
"size":"",
"date":"01/20/2010",
"children":[{
"id":31,
"name":"eclipse.exe",
"size":"56 KB",
"date":"05/19/2009"
},{
"id":32,
"name":"eclipse.ini",
"size":"1 KB",
"date":"04/20/2010"
},{
"id":33,
"name":"notice.html",
"size":"7 KB",
"date":"03/17/2005"
}]
}]
}]

查询出来的list列表
List<MeModule> list = moduleService.findList();

Answer 1

首先没太明白你的意思
List<Map<String,Object>> list = moduleService.findList(); 然后return list; 就可以获取到list的值了。 前台使用 post方法 返回个data 然后 data[i].XX 就可以得到你需要的值了 easyui 中 例如 id 是 validatebox 格式 赋值就是

$('#id').val(data[0].id);