Question

判断QButtonGroup中哪个QRadioButton被选中

Answer 1

T qobject_cast ( QObject * object )如果object是T类型或者它的子类，就可以把object返回成T类型对象。否则返回0。类T必须是QObject的子类，而且必须声明宏：Q_OBJECTExample: Cpp代码 QObject *obj = new QTimer; // QTimer inherits QObject QTimer *timer = qobject_cast<QTimer *>(obj); // timer == (QObject *)obj QAbstractButton *button = qobject_cast<QAbstractButton *>(obj); // button == 0 问题 方法1、可以通过对象名称去判断Cpp代码 QAbstractButton *radioButton = qobject_cast<QAbstractButton *> (ui.buttonGroup_1->checkedButton()); //ui.buttonGroup_1->checkedButton() 返回一个QRadioButton对象 //将它转换成QAbstractButton //，通过对象名称去判断 if(QString::compare(radioButton->objectName(), "topTubePositionRadio", Qt::CaseSensitive)) tubePosition = 0; else if(QString::compare(radioButton->objectName(), "bottomTubePositionRadio", Qt::CaseSensitive)) tubePosition = 1; else if (QString::compare(radioButton->objectName(), "lateralTubePositionRadio", Qt::CaseSensitive)) tubePosition = 2;
方法2：通过checkedId去判断首先需要在界面被激活初始化设置buttonGroup中的IdCpp代码 ui.buttonGroup_1->setId(ui.topTubePositionRadio,0);//topTubePositionRadio的Id设为0 ui.buttonGroup_1->setId(ui.bottomTubePositionRadio,1); ui.buttonGroup_1->setId(ui.lateralTubePositionRadio,2);
然后在你想获取哪个radioButton被选中时直接获取checkedId值，最后判断一下这个Id值就可以了。quint16 a = ui.buttonGroup_1->checkedId(); 很纳闷为啥QtDesigner中没有界面直接赋给这个radioButton，Id值？？？？？或许是没有必要吧，第一种方法也可以。