
1个回答
展开全部
∫[0:2]x²√(x³+1)dx
=⅓∫[0:2]√(x³+1)d(x³+1)
=⅓·⅔(x³+1)^(3/2)|[0:2]
=(2/9)[(2³+1)^(3/2) -(0³+1)^(3/2)]
=(2/9)(27-1)
=52/9
average=(52/9)/(2-0)=26/9
选A
=⅓∫[0:2]√(x³+1)d(x³+1)
=⅓·⅔(x³+1)^(3/2)|[0:2]
=(2/9)[(2³+1)^(3/2) -(0³+1)^(3/2)]
=(2/9)(27-1)
=52/9
average=(52/9)/(2-0)=26/9
选A
追问
牛皮
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询