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∫[0:2]x²√(x³+1)dx
=⅓∫[0:2]√(x³+1)d(x³+1)
=⅓·⅔(x³+1)^(3/2)|[0:2]
=(2/9)[(2³+1)^(3/2) -(0³+1)^(3/2)]
=(2/9)(27-1)
=52/9
average=(52/9)/(2-0)=26/9
选A
=⅓∫[0:2]√(x³+1)d(x³+1)
=⅓·⅔(x³+1)^(3/2)|[0:2]
=(2/9)[(2³+1)^(3/2) -(0³+1)^(3/2)]
=(2/9)(27-1)
=52/9
average=(52/9)/(2-0)=26/9
选A
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