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第三小题,求大神解答!
1个回答
展开全部
2a²-[1/2(ab-a²)+8ab]-1/2ab
=2a²-[(1/2)ab-(1/2)a²+8ab]-(1/2)ab
=2a²-(1/2)ab+(1/2)a²-8ab-(1/2)ab
=2a²-ab+(1/2)a²-8ab
=(3/2)a²-9ab
=2a²-[(1/2)ab-(1/2)a²+8ab]-(1/2)ab
=2a²-(1/2)ab+(1/2)a²-8ab-(1/2)ab
=2a²-ab+(1/2)a²-8ab
=(3/2)a²-9ab
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