第7题选啥?
2个回答
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x^2-mx+2m-1=0
x1+x2 = m
x1.x2=2m-1
(x1)^2 +(x2)^2 =7
(x1+x2)^2 -2x1.x2 =7
m^2-2(2m-1) = 7
m^2-4m-5=0
(m-5)(m+1)=0
m=5 or -1
ans: C
x1+x2 = m
x1.x2=2m-1
(x1)^2 +(x2)^2 =7
(x1+x2)^2 -2x1.x2 =7
m^2-2(2m-1) = 7
m^2-4m-5=0
(m-5)(m+1)=0
m=5 or -1
ans: C
更多追问追答
追答
(x^2-4)/(x^2-4x+4)
=(x-2)(x+2)/(x-2)^2
=(x+2)/(x-2)
(x^2-4)/(x^2-4x+4) + (2-x)/(x+2)
=(x+2)/(x-2) -(x-2)/(x+2)
=8x/(x-2)(x+2)
[(x^2-4)/(x^2-4x+4) + (2-x)/(x+2)] / (x/(x-2) ]
=[8x/(x-2)(x+2)] . (x-2)/x
=8/(x+2)
ans :D
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