高数答疑 求导数
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y=(x-1) . [(x-2)^2/(x-3)]^(1/3)
lny = ln(x-1) + (1/3)[ 2ln(x-2) -ln(x-3) ]
y'/y = 1/(x-1) + (1/3)[ 2/(x-2) -1/(x-3) ]
y' ={ 1/(x-1) + (1/3)[ 2/(x-2) -1/(x-3) ] }.(x-1) . [(x-2)^2/(x-3)]^(1/3)
lny = ln(x-1) + (1/3)[ 2ln(x-2) -ln(x-3) ]
y'/y = 1/(x-1) + (1/3)[ 2/(x-2) -1/(x-3) ]
y' ={ 1/(x-1) + (1/3)[ 2/(x-2) -1/(x-3) ] }.(x-1) . [(x-2)^2/(x-3)]^(1/3)
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