Question

(x的2次幂y的3次幂)的-2次幂×（xy的2次幂）÷（x的2次幂y）的-1次幂

Answer 1

解：原式
=
(x
2
y
3
)
-2
×(xy
2
)÷(x
2
y)
-1
=
(x
-4
y
-6
)×(xy
2
)×(x
2
y)
=
(x
-4

·x·x
2
)×(y
-6
·y
2
·y)
=
x
-1
y
-3
=
1/(xy­
3
)
。