复合函数求导问题,我怎么算不出来?
3个回答
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y=ln[x+√(x^2+1)]
y'
={1/[x+√(x^2+1)]} .[x+√(x^2+1)]'
={1/[x+√(x^2+1)]} .{ (x)'+ [√(x^2+1)]' }
={1/[x+√(x^2+1)]} .[1+ x/√(x^2+1)]
={1/[x+√(x^2+1)]} .{ [x+√(x^2+1)]/√(x^2+1) }
=1/√(x^2+1)
y'
={1/[x+√(x^2+1)]} .[x+√(x^2+1)]'
={1/[x+√(x^2+1)]} .{ (x)'+ [√(x^2+1)]' }
={1/[x+√(x^2+1)]} .[1+ x/√(x^2+1)]
={1/[x+√(x^2+1)]} .{ [x+√(x^2+1)]/√(x^2+1) }
=1/√(x^2+1)
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