Question

根号2+2sin(2π-θ)-cos^2(π+θ)可化简为？

Answer 1

=根(sin^2(π+θ)+cos^2(π+θ)+1-+2sin(π+θ)cos^2(π+θ))
=根（sin^2(π+θ)+2sin(π+θ)+1）
=根（(sin(π+θ)+1)^2）
=根（(1-sinθ)^2）
=|sinθ-1|,6,根号2+2sin(2π-θ)-cos^2(π+θ)可化简为
前面是根号下